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Question #127 Difficulty: 3

According to the C++23 standard, what is the output of this program? 

    #include <iostream>
#include <type_traits>

int main()
{
  int i, &j = i;
  [=]
  {
    std::cout << std::is_same<decltype    ((j)),     int         >::value
              << std::is_same<decltype   (((j))),    int      &  >::value
              << std::is_same<decltype  ((((j)))),   int const&  >::value
              << std::is_same<decltype (((((j))))),  int      && >::value
              << std::is_same<decltype((((((j)))))), int const&& >::value;
  }();
}

Hint:

[=] captures by copy.

There's an important difference between decltype(j) and decltype((j)).

What is the constness of the lambda's operator()?

Answer:

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