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Question #251 Difficulty: 2

According to the C++17 standard, what is the output of this program? 

    #include <iostream>

template<class T>
void f(T) { std::cout << 1; }

template<>
void f<>(int*) { std::cout << 2; }

template<class T>
void f(T*) { std::cout << 3; }

int main() {
    int *p = nullptr; 
    f( p );
}

Hint:

A declaration of a function template being explicitly specialized shall precede the declaration of the explicit specialization.
During overload resolution, only the base function templates are considered, not specialisations.

Answer:

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