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Question #347 Difficulty: 2

According to the C++23 standard, what is the output of this program? 

    #include <iostream>
#include <type_traits>

template <typename T>
void foo(T& x)
{
    std::cout << std::is_same_v<const int, T>;
}

template <typename T>
void bar(const T& x)
{
    std::cout << std::is_same_v<const int, T>;
}

int main()
{
    const int i{};
    int j{};

    foo(i);
    foo(j);
    bar(i);
    bar(j);
}

Hint:

If a parameter is of a reference type, the type referred to is used for type deduction. Also, it is allowed to deduce an argument type to a more cv-qualified type.

Answer:

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